2.3*10^-9=(0.15-x)(x)

Solution for 2.3*10^-9=(0.15-x)(x) equation:

2.3*10^-9=(0.15-x)(x)

We move all terms to the left:

2.3*10^-9-((0.15-x)(x))=0

We add all the numbers together, and all the variables

-((-1x+0.15)x)-9+2.3*10^=0

We add all the numbers together, and all the variables

-((-1x+0.15)x)=0


We calculate terms in parentheses: -((-1x+0.15)x), so:

(-1x+0.15)x

We multiply parentheses

-1x^2+0.15x

Back to the equation:

-(-1x^2+0.15x)


We get rid of parentheses

1x^2-0.15x=0

We add all the numbers together, and all the variables

x^2-0.15x=0

a = 1; b = -0.15; c = 0;
Δ = b2-4ac
Δ = -0.152-4·1·0
Δ = 0.0225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.15)-\sqrt{0.0225}}{2*1}=\frac{0.15-\sqrt{0.0225}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.15)+\sqrt{0.0225}}{2*1}=\frac{0.15+\sqrt{0.0225}}{2}
$